x^2+70x-3000=0

Solution for x^2+70x-3000=0 equation:

x^2+70x-3000=0

a = 1; b = 70; c = -3000;
Δ = b2-4ac
Δ = 702-4·1·(-3000)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-130}{2*1}=\frac{-200}{2}
=-100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+130}{2*1}=\frac{60}{2}
=30
$